program mountain;
Uses Math;
const
MAXN = 100005;
var
ANS, N, i, j, maxMountainLength : LongInt;
P, leftLIS, rightLIS, scartato : Array[0..MAXN-1] of LongInt;
begin
(*assign(input, 'input.txt'); reset(input);
assign(output, 'output.txt'); rewrite(output);*)
ReadLn(N);
for i:=0 to N-1 do
Read(P[i]);
ReadLn();
ANS := 0;
(*leftLIS[i] stores the length of longest increasing subsequence ending at index i*)
(*rightLIS[i] stores the length of longest decreasing subsequence starting at index i*)
for i:=0 to N-1 do begin leftLIS[i]:=1; rightLIS[i]:=1; scartato[i]:=0; end;
(*Calculate LIS from left to right for each position*)
for i := 1 to N-1 do
for j:= 0 to i-1 do
begin
if (i<N-1) and (P[i]<P[i-1]) and (P[i]<P[i+1]) then scartato[i]:=1;
if (j>0) and (P[j]<P[j-1]) and (P[j]<P[j+1]) then scartato[j]:=1;
if (scartato[i]=0) and (scartato[j]=0) and (P[i] > P[j]) then leftLIS[i] := max(leftLIS[i], leftLIS[j] + 1);
end;
(* Calculate LIS from right to left (decreasing subsequence) for each position*)
for i := N - 2 downto 0 do
for j := i + 1 to N-1 do
begin
if (i>0) and (P[i]<P[i-1]) and (P[i]<P[i+1]) then scartato[i]:=1;
if (j<N-1) and (P[j]<P[j-1]) and (P[j]<P[j+1]) then scartato[j]:=1;
if (scartato[i]=0) and (scartato[j]=0) and (P[i] > P[j]) then rightLIS[i] := max(rightLIS[i], rightLIS[j] + 1);
end;
(* Find the maximum length of mountain subsequence*)
maxMountainLength := 0;
for i := 0 to N-1 do
(*A valid mountain peak must have at least one element on both sides*)
(*leftLIS[i] > 1 ensures there's at least one element before peak*)
(*rightLIS[i] > 1 ensures there's at least one element after peak*)
if (leftLIS[i] >= 1) and (rightLIS[i] >= 1) then
(*Total mountain length with peak at i Subtract 1 because peak is counted in both leftLIS and rightLIS*)
maxMountainLength := max(maxMountainLength, leftLIS[i] + rightLIS[i] - 1);
(* Minimum removals = total elements - maximum mountain length*)
ANS:= N - maxMountainLength;
WriteLn(ANS);
end.